Talk:Clock rate: Difference between revisions
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Interestingly, there is even two more unused bits on this divider (off the bottom), so maybe by the time they made the 2A03G's die they had unified the 2A07 and 2A03 designs sufficiently to just be a "move this tap from here to here". | Interestingly, there is even two more unused bits on this divider (off the bottom), so maybe by the time they made the 2A03G's die they had unified the 2A07 and 2A03 designs sufficiently to just be a "move this tap from here to here". | ||
Dividing by 15 would have required an entire different design, and I suspect that the smallest ÷15 circuit (4 bit binary counter plus 4-input AND gate) would have taken more silicon die space than the 8-stage Johnson counter they used. | |||
—[[User:Lidnariq|Lidnariq]] 00:05, 4 September 2012 (MDT) | —[[User:Lidnariq|Lidnariq]] 00:05, 4 September 2012 (MDT) | ||
Revision as of 06:13, 4 September 2012
Divider
Ok, ok. I went to the visual2A03, saw that Quietust had implemented a "microstep" function which drives the 2A03's clock input (instead of the inside 6502's φ0 input), and so tested this. In the 2A03, the input clock is implemented using a Johnson counter, which intrinsically divides by an even number. They couldn't use the same design to divide by 15, so they instead divided by 16.
Interestingly, there is even two more unused bits on this divider (off the bottom), so maybe by the time they made the 2A03G's die they had unified the 2A07 and 2A03 designs sufficiently to just be a "move this tap from here to here".
Dividing by 15 would have required an entire different design, and I suspect that the smallest ÷15 circuit (4 bit binary counter plus 4-input AND gate) would have taken more silicon die space than the 8-stage Johnson counter they used. —Lidnariq 00:05, 4 September 2012 (MDT)
